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A refrigerator operates on the reversed Carnot cycle. The cold reservoir temperature is 250 \mathrm{~K} and the hot reservoir temperature is 500 \mathrm{~K}. The refrigerator is used to cool an interior space to 275 \mathrm{~K}.Calculate the coefficient of performance (COP) of the refrigerator.
 

Option: 1

1


Option: 2

17


Option: 3

20


Option: 4

20


Answers (1)

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The coefficient of performance (COP) of a refrigerator operating on the reversed Carnot cycle is given by:
\mathrm{\mathrm{COP}=\frac{T_{\text {cold }}}{T_{\text {hot }}-T_{\text {cold }}} }

Given that \mathrm{T_{\text {cold }}=250 \mathrm{~K} and T_{\text {hot }}=500 \mathrm{~K} }, we can calculate the COP:

\mathrm{\mathrm{COP}=\frac{250 \mathrm{~K}}{500 \mathrm{~K}-250 \mathrm{~K}}=\frac{250 \mathrm{~K}}{250 \mathrm{~K}}=1 }
Therefore, the coefficient of performance \mathrm{(\mathrm{COP}) } of the refrigerator is 1 .

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avinash.dongre

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