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A right-angled triangle abc, made from a metallic wire, moves at a uniform speed v in its plane as shown in figure. A uniform magnetic field B exists in the perpendicular direction. The emf induced in the loop abc, in the segment bc, in the segment ac and in the segment ab are:

Option: 1

\mathrm{zero; \mathrm{vB}(\mathrm{bc}),+ ve \; at \mathrm{c}, zero, \mathrm{vB}(\mathrm{bc}), +ve\; at \; a}


Option: 2

\mathrm{\mathrm{vB}\: (\mathrm{bc}), + ve\: at \: c, zero; \: zero;\: \mathrm{vB}(\mathrm{bc}), + ve\: at\: a}


Option: 3

\mathrm{\mathrm{zero; zero; \mathrm{vB}(\mathrm{bc}), + ve \: at\: \mathrm{c}, \mathrm{vB}(\mathrm{bc}), + ve\: at\: a}}


Option: 4

\mathrm{\mathrm{vB}(\mathrm{bc}), + ve \: at\: \mathrm{c}, \mathrm{vB}(\mathrm{bc}), +ve \: at\: a; zero; zero}


Answers (1)

best_answer

For segment ac, emf ac : e = 0
For segment ab, emf ab:

 

Posted by

Irshad Anwar

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