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A ring and a solid sphere rotating about an axis passing trough their centers have same radii of gyration. The axis of rotation is perpendicular to plane of ring. The ratio of radius of ring to that of sphere is   \sqrt{\frac{2}{x}}.   The value of x is ______.

Option: 1

5


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Given radius of gyration is the same for the ring and solid sphere

\begin{aligned} & \mathrm{K}_{\mathrm{R}}=\mathrm{K}_{\mathrm{ss}} \\ & \mathrm{R}_{\mathrm{R}}=\sqrt{\frac{2}{5}} \mathrm{R}_{\mathrm{ss}} \\ & \text { or } \frac{\mathrm{R}_{\mathrm{R}}}{\mathrm{R}_{\mathrm{ss}}}=\sqrt{\frac{2}{5}} \end{aligned}

therefore x = 5

Posted by

Suraj Bhandari

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