Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A salt made of bivalent ions X and Y, each of which is capable of decolourising acidified KMnO4 solution. The salt is likely to be:Option: 1

A salt made of bivalent ions X and Y, each of which is capable of decolourising acidified KMnO4 solution. The salt is likely to be:

Option: 1

Ferrous oxalate


Option: 2

Ferric chloride


Option: 3

Ferrous sulphate


Option: 4

Stannic chloride


Answers (1)

best_answer

As we have learnt,

Ferrous oxalate consists of Fe^{2+} and C_2O_4^{2-}ions. Both act as reducing agents and decolorise acidifed KMnO4 solution. The reactions occur as follows:

\\\mathrm{2MnO_{4}^{-}\: +\: 16H^{+}\: +\: 10Fe^{2+}\: \rightarrow \: 10Fe^{3+}\: +\: 2Mn^{2+}\: +\: 8H_{2}O}\\\\\mathrm{2MnO_{4}^{-}\: +\: 16H^{+}\: +\: 5C_{2}O_{4}^{2-}\: \rightarrow \: 2Mn^{2+}\: +\: 10CO_{2}\: +\: 8H_{2}O}

Therefore, Option(1) is correct.

Posted by

HARSH KANKARIA

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: 2nd attempt? Mistakes to avoid, tips to improve score, percentile
anam-khan

JEE Main 2025: What to expect on exam day? Section-wise paper pattern, marking scheme, last-minute tips
anam-khan

JEE Main 2025 Live: NTA JEE session 2 exams from tomorrow; updates on admit card, exam pattern, passing marks

Latest Question