A sample of oleum is labelled as 104.5%. What is the percentage of free SO3 in the sample?
20%
40%
60%
80%
Weight of H2O added = 4.5 g
Moles of H2O added = 0.25
Moles of SO3 present = 0.25
Weight of SO3 in the 100g Oleum sample = 0.25 80 = 20 g
% of free SO3 in Oleum = 20 %
Hence, the correct option is (1)
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