Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A satelete is in an all optical orbit around planet P. It is observed that the velocity of the satelite when it is farthest from the planet is 6 times less than that when it is closest to the planet. The ratio of distances b/w the satelite and the plan

A satelete is in an all optical orbit around planet P. It is observed that the velocity of the satelite when it is farthest from the planet is 6 times less than that when it is closest to the planet. The ratio of distances b/w the satelite and the planet at closest and farthest point is :-
 
Option: 1 3:4
Option: 2 1:6
Option: 3 1:2  
Option: 4 1:3

Answers (1)

best_answer

As the angular momentum remains conserved. So,

L_{Nearest} = L_{Farthest}

m \times v_n \times r_n = m \times v_f \times r_f

Also,

V_{f}=\frac{V_{n}}{6}

As,

V_{n} \times r_{n}={V}_{f} \times{r}_{f}

V_{n} \times r_{n}=\frac{V_n}{6} \times{r}_{f}

So,

\frac{r_n}{r_f} = \frac{1}{6}

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: Wider gap in NIT cut-offs for home and other-state quotas; outsiders need better rank
anam-khan

JEE Mains 2026: Use of calculator 'not allowed’ says NTA; cites ‘typographical error' in information bulletin
anam-khan

JEE Main 2026: NIT Warangal attracts best talent with high BTech cut-offs in top, emerging branches

Latest Question