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  • A semiconductor has an electron concentration of <img alt="\mathrm{0.45\times 10^{12}/m^{3}}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B0.45%5Ctimes%2010%5E%7B12%7D/m%5E

A semiconductor has an electron concentration of \mathrm{0.45\times 10^{12}/m^{3}} and a hole concentration of \mathrm{5\times 10^{20}/m^{3}}.Its conductivity

is:\mathrm{\left(\mu_{\mathrm{e}}=0.135 \mathrm{~m}^2 / \mathrm{V}-\mathrm{S}, \mu_{\mathrm{h}}=0.048 \mathrm{~m}^2/ V-\mathrm{s}\right) .}

Option: 1

\mathrm{zero}


Option: 2

\mathrm{1.84 \Omega^{-1}-\mathrm{m}^{-1}}


Option: 3

\mathrm{2.84 \Omega^{-1}-m^{-1}}


Option: 4

\mathrm{3.84 \Omega^{-1}-m^{-1}}


Answers (1)

best_answer

The conductivity, \mathrm{\sigma} of the semiconductor is given by

\mathrm{\begin{aligned} & \sigma=\mathrm{e}\left(n_e \mu_e+n_n \mu_h\right) \\ & =1.6 \times 10^{-19}\left(0.45 \times 10^{12} \times 0.135+5 \times 10^{20} \times 0.048\right) \\ & =3.84 \Omega^{-1}-\mathrm{m}^{-1} . \end{aligned}}

Posted by

seema garhwal

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