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A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is ______\mathrm{Hz}.

Option: 1

152


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{f, f+4, \& f+8 \ldots, 2 f}
For \mathrm{n^{\text {th }}} term in arithmetic progression,

\mathrm{t_{n}=a+(n-1) d}
\mathrm{2 f =f+(20-1) 4}
\mathrm{2 f =f+76}
\mathrm{f=76 \mathrm{~Hz}}

The frequency of the last fork is
\mathrm{2 f=152\, \mathrm{Hz}}

Posted by

Riya

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