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A short bar magnet with its north plane, the net magnetic induction at P is: (Horizontal component of earth's magnetic field = BH ) . A short bar magnet with its north pole facing north forms a neutral point at P in the horizontal plane. It the magnet is rotated by 90^{\circ} in the horizontal.

Option: 1

0


Option: 2

2 \mathrm{~B}_{\mathrm{H}}


Option: 3

\mathrm{\frac{\sqrt{5}}{2} B_H}


Option: 4

\sqrt{5} \mathrm{~B}_{\mathrm{H}}


Answers (1)

best_answer

At P
\mathrm{B_H=B_M} (equatorial) in opposite direction After turning magnet, P now at axial point \mathrm{B_H ~\& ~2 B_M} perpendicular
\mathrm{ \text { net }=\sqrt{\mathrm{B}_{\mathrm{H}}^2+\left(2 \mathrm{~B}_{\mathrm{H}}\right)^2}=\sqrt{5 \mathrm{~B}_{\mathrm{H}}} }

Posted by

Kuldeep Maurya

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