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A small block of mass 100 g is tied to a spring of spring constant 7.5 N/m and length 20 cm. The other end of
spring is fixed at a particular point A. If the block moves in a circular path on a smooth horizontal surface with
constant angular velocity 5 rad/s about point A, then tension in the spring is –

Option: 1

0.75N


Option: 2

1.5N


Option: 3

0.25 N


Option: 4

0.50 N


Answers (1)

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\begin{aligned} & k x=m \omega^2 r \\ & \Rightarrow k x=0.1 \times 25 \times(0.2+x) \\ & \Rightarrow 7.5 x=2.5(0.2+x) \\ & \Rightarrow 3 x=0.2+x \\ & \Rightarrow 2 x=0.2 \\ & \Rightarrow x=0.1 \mathrm{~m} \end{aligned} \\ \text{Now, tension in the spring } =k x=7.5 \times 0.1 \mathrm{~N}=0.75 \mathrm{~N}

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Divya Prakash Singh

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