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  • A solenoid of length 30 cm with 10 turns per centimetre and area of cross – section <img alt="\mathrm{40 \mathrm{~cm}^2}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B40%2

A solenoid of length 30 cm with 10 turns per centimetre and area of cross – section \mathrm{40 \mathrm{~cm}^2} completely surrounds another co-axial solenoid of same length, area of cross – section 20 2 cm with turns per centimetre. The mutual inductance of the system is:

Option: 1

10 H


Option: 2

8 H


Option: 3

3 mH


Option: 4

30 mH


Answers (1)

best_answer

Mutual inductance of the system\mathrm{M=\mu_0 n_1 n_2 A_{2 i}}

Where \mathrm{A_{2}} is the area of inner solenoid.

\mathrm{\begin{aligned} & \mathrm{n}_1=10 \mathrm{~cm}^{-1}=1000 \mathrm{~m}^{-1} \\ & \mathrm{n}_2=40 \mathrm{~cm}^{-1}=4000 \mathrm{~m}^{-1} \\ & l=30 \mathrm{~cm}=30 \times 10^{-2} \mathrm{~m} \\ & \mathrm{~A}_2=20 \mathrm{~cm}^2=20 \times 10^{-4} \mathrm{~m}^2 \\ & \therefore \mathrm{M}=4 \pi \times 10^{-7} \times 1000 \times 4000 \times 20 \times 10^{-4} \times 30 \times 10^{-2}=301.44 \times 10^{-5} \mathrm{H}=3 \mathrm{mH} \end{aligned}}

 

Posted by

Gautam harsolia

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