Get Answers to all your Questions

header-bg qa

A solid cylinder length is suspended symmetrically through two massless strings, as shown in the figure. The distance from the initial rest position, the cylinder should by unbinding the strings to achieve a speed of 4 \mathrm{~ms}^{-1}, is ________\mathrm{cm} .( take \mathrm{g}=10 \mathrm{~ms}^{-2})

Option: 1

120


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{2 T R=I \alpha=\frac{M R^2}{2} \alpha}

\mathrm{T=\frac{M R \alpha}{4} \rightarrow(1)}

\mathrm{M g-2 T=M a_{\mathrm{cm}} \rightarrow \text { (2) }}

\mathrm{a_{\mathrm{cm}}=R \alpha \text { (for pure rolling motion) }}

\mathrm{M g=\frac{3 M a_{\mathrm{cm}}}{2}}

\mathrm{a_{c m}=\frac{29}{3}}

\mathrm{v^2 =u^2+2 a s}

\mathrm{16^0=0+2 \times \frac{29}{3}s}

\mathrm{s=1.2m}

\mathrm{s=120cm}

Posted by

Divya Prakash Singh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE