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A Spherical ball of radius 1 \mathrm{~mm} and density 10.5 \mathrm{~g} / \mathrm{cc} is dropped in glycerine of coefficient of viscosity 9.8 poise and density 1.5 \mathrm{~g} / \mathrm{cc}. Viscous force on the ball when it attains constant velocity is 3696 \times$ $10^{-x} \mathrm{~N}. The value of \mathrm{x}. is (Given, \mathrm{g=9.8 \mathrm{~m} / \mathrm{s}^2 \: and \: \pi=\frac{22}{7}} )

 

Option: 1

7


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{V}_{\mathrm{T}}=\frac{2 \mathrm{r}^2 \mathrm{~g}\left(\sigma_{\mathrm{s}}-\rho_t\right)}{\mathrm{a}_{\mathrm{n}}} \\ \end{aligned}

\begin{aligned} & \frac{2 \times 10^{-6} \times 9.8 \times(10.5-1.5) \times 10^3}{9.8 \times 0.1 \times 9} \\ \end{aligned}

\begin{aligned} & =2 \times 10^{-2} \mathrm{~m} / \mathrm{s} \\ \end{aligned}

\begin{aligned} & \mathrm{F}=6 \pi \mathrm{r} \mathrm{V}_{\mathrm{T}} \\ \end{aligned}

\begin{aligned} & =6 \times \frac{22}{7} \times 9.8 \times 0.1 \times 10^{-3} \times 18 \times 10^{-2} \\ \end{aligned}

\begin{aligned} & =3696 \times 10^{-7} \\ & =7 \end{aligned}

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jitender.kumar

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