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A spherical soap bubble of radius 3 \mathrm{~cm} is formed inside another spherical soap bubble of radius 6 \mathrm{~cm}. If the internal pressure of the smaller bubble of radius 3 \mathrm{~cm} in the above system is equal to the internal pressure of the another single soap bubble of radius \mathrm{r}\: \: \mathrm{cm}. The value of \mathrm{r}  is___________.

Option: 1

2 cm


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{P_{i}-P=\frac{4T}{r_{1}}}

\mathrm{P-P_{o}=\frac{4T}{r_{2}}}

\mathrm{P_{i}-P_{o}=\frac{4T}{r_{1}}+\frac{4T}{r_{2}}}\rightarrow (1)

\mathrm{P_{i}-P_{o}=\frac{4T}{r}}\rightarrow (2)

From eq. (1) and (2)

\mathrm{\frac{4t}{r}=\frac{4T}{r_{1}}+\frac{4T}{r_{2}}\left ( Given \right )}

\mathrm{\frac{1}{r}=\frac{1}{r_{1}}+\frac{1}{r_{2}}}

    =\frac{1}{3}+\frac{1}{6}=\frac{9}{18}

\mathrm{r=2cm}

Posted by

Irshad Anwar

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