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  • A square aluminum <img alt="\mathrm{ (shear \; modulus \; is \; 25 \times 10^{9} \mathrm{Nm}^{-2} ) }" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%20%28shear%20%5C%3B%20m

A square aluminum \mathrm{ (shear \; modulus \; is \; 25 \times 10^{9} \mathrm{Nm}^{-2} ) } slab of side \mathrm{ 60 \mathrm{~cm}} and thickness \mathrm{ 15 \mathrm{~cm} } is subjected to a shearing force (on its narrow face) of \mathrm{ 18.0 \times 10^{4} \mathrm{N}. }The lower edge is riveted to the floor. The displacement of the upper edge is ____________ \mathrm{ \mu \mathrm{m} .}

Option: 1

48


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{A=15\times 16=900\times 10^{-4}m^{2}}

\mathrm{F =18 \times 10^4 }

\mathrm{\eta =\frac{F / A}{(x / \ell)} }

\mathrm{25 \times 10^9 =\frac{18 \times 10^4}{900 \times 10^{-4}} \times \frac{x}{60 \times 10^{-2}} }

\mathrm{x =\frac{60 \times 10^{-2} \times 10^8}{50 \times 25 \times 10^9} }

\mathrm{=4.8 \times 10^{-3} \times 10^{-2} }

\mathrm{x =48 \mathrm{\mu m}}








 

Posted by

jitender.kumar

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