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A square loop ABCD, carried a current i is placed near and coplanar with a long Straight conductor XY carrying a current i, the net force on the loop will be

 

Option: 1

\frac{2\mu_0 I i}{3 \pi}


Option: 2

\frac{\mu_0 I i}{2\pi}


Option: 3

\frac{2 { \mu_0 I L }}{3 \pi}

 


Option: 4

\frac{\mu_0 I i L}{2 \pi}


Answers (1)

best_answer

\begin{aligned} f_{\text {net }} & =\frac{\mu_0 I i L}{2 \pi L / 2}(-\hat{i})+\frac{\mu_0 I i L}{2 \pi\left(\frac{3 L}{2}\right)} \hat{i} \\ & =\frac{\mu_0 I i L}{\pi L}\left(1-\frac{1}{3}\right) \\ & =\frac{2 \mu_0 I i}{3 \pi} \end{aligned}

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Irshad Anwar

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