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  • A steel wire of cross-sectional area 3 X 10-6 m2 can withstand a maximum strain of 10-3 . Young's modulus of steel is 2 X 1011</su

A steel wire of cross-sectional area 3 X 10-6 m2 can withstand a maximum strain of 10-3 . Young's modulus of steel is 2 X 1011 N/m2. The maximum mass this wire can hold is -  

Option: 1

60 kg


Option: 2

70 kg


Option: 3

80 kg


Option: 4

100 kg


Answers (1)

best_answer

Maximum stress = Y x (maximum strain)

\frac{Mg}{A} = 2 \, \times \, 10^{11}\, \times \, 10^{-3} = 2 \, \times \, 10^{8}

M=\frac{2\, \times \, 10^{8}\, \times \, 3\, \times \, 10^{-6}}{10}

M = 6 X 102 X 10-1 

    = 6 X 10

M = 60 kg

Posted by

Rakesh

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