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  • A stone of mass is tied to end of a massless string of length <img alt="1 \mathrm{~m}" sr

A stone of mass 1 \mathrm{~kg} is tied to end of a massless string of length 1 \mathrm{~m}.If the breaking tension of the string is 400 \mathrm{~N}, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is :

Option: 1

40 \mathrm{~ms}^{-1}


Option: 2

400 \mathrm{~ms}^{-1}


Option: 3

20 \mathrm{~ms}^{-1}


Option: 4

10 \mathrm{~ms}^{-1}


Answers (1)

best_answer



\mathrm{T= \frac{mv^{2}}{\iota }}
400=\frac{1 \times v^{2}}{1}
\mathrm{V}=20 \mathrm{~m} / \mathrm{s}

Posted by

Riya

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