Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A stone of mass is tied to end of a massless string of length <img alt="1 \mathrm{~m}" sr

A stone of mass 1 \mathrm{~kg} is tied to end of a massless string of length 1 \mathrm{~m}.If the breaking tension of the string is 400 \mathrm{~N}, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is :

Option: 1

40 \mathrm{~ms}^{-1}


Option: 2

400 \mathrm{~ms}^{-1}


Option: 3

20 \mathrm{~ms}^{-1}


Option: 4

10 \mathrm{~ms}^{-1}


Answers (1)

best_answer



\mathrm{T= \frac{mv^{2}}{\iota }}
400=\frac{1 \times v^{2}}{1}
\mathrm{V}=20 \mathrm{~m} / \mathrm{s}

Posted by

Riya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2025 session 1 registration deadline on November 22; apply on jeemain.nta.nic.in
anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'

Latest Question