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A stone with a mass of  150\ g rotates around a horizontal circle at a speed of 10\ \frac{m}{s} and a attached to the end of a rope   1m long. What is the centripetal acceleration  of the stone?

Option: 1

100\ \frac{m}{s^2}


Option: 2

50\ \frac{m}{s^2}


Option: 3

80\frac{m}{s^2}


Option: 4

10\frac{m}{s^2}


Answers (1)

best_answer

Since the centripetal force:

F_c=\frac{mv^2}{r}= \frac{0.15\times 102}{01}=15\ N
Now,
Using Newton's second law the centripetal acceleration can be calculated as

a_c=\frac{F_c}{m}= \frac{15}{0.15}=100\ m= 100\frac{m}{s^2}

Posted by

Ritika Harsh

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