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A stress of 10^6\, N/m^{2} is required for breaking a material. If the density of the material is 3 \times 10^3\, kg/m^{3}, what should be the length of the wire made of this material so that it breaks under its own weight?

Option: 1

10 m


Option: 2

33.3 m


Option: 3

10 cm


Option: 4

40 m


Answers (1)

best_answer

\frac{m g}{A}= \text {maximum\: breaking\: stress}\\\\\ or \frac{(A l P) g}{A}=\sigma_{\max }\\\\ \begin{aligned} \therefore \quad l_{\text {max }} & =\frac{\sigma_{\max }}{\rho g} l_{\text {max }}\\\ & =\frac{10^6}{\left(3 \times 10^3\right) 10}=3.33 \times 10^{0} \\ & =3.33 \mathrm{~m} \end{aligned}

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Riya

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