Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A stretched rope having linear mass density <img alt="5 \times 10^{-2} \mathrm{~kg} / \mathrm{m}" src="https://entrancecorner.oncodecogs.com/gif.latex?5%20%5Ctimes%2010%5E%7B-2%7D%20%5Cmathrm%

A stretched rope having linear mass density 5 \times 10^{-2} \mathrm{~kg} / \mathrm{m} is under a tension of 80N. The power that has to be supplied to the rope to generate harmonic waves at a frequency of 80Hz and amplitude of 6cm is-

Option: 1

362w


Option: 2

251w


Option: 3

511w


Option: 4

416w


Answers (1)

best_answer

\begin{aligned} Use,\ \sqrt{\frac{\epsilon}{\rho}} & =10 \sqrt{\frac{T}{\mu}} \Rightarrow 100\left(\frac{T}{\mu}\right)=\frac{\epsilon}{\rho} \\ \frac{T}{S} & =\frac{\epsilon \mu}{100 \rho S} \\ But,\ \rho S & =\mu, \quad \text { strcss }=\frac{T}{S}=\frac{E}{100} \end{aligned}

Posted by

Info Expert 30

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA Exam 2025 Live: UGC NET admit card out for all exams; JEE Main session 1 hall ticket soon
anam-khan

SFI protests across Tamil Nadu universities against UGC draft regulations on faculty recruitment
anam-khan

How to get top rank in JEE Main 2025? Last 10-day study plan

Latest Question