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  • A swimmer wants to cross a river from point to point . Line makes an angle of <img alt="30^{

A swimmer wants to cross a river from point A to point \mathrm{B}. Line \mathrm{AB} makes an angle of 30^{\circ} with the flow of river. Magnitude of velocity of the swimmer is same as that of the river. The angle \theta with the line \mathrm{AB} should be _______^{0},swimmer reaches point B.
 

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{\bar{V}_{M / G}}={\bar{V}_{M / R}}+{\bar{V}_{R}}

\bar{V}_{M / G} \rightarrow Velocity \: of \: swimmer \: with \: ground

V_{M/G} must \: be \: along \: A B$ to reach pt. $B

\begin{aligned} V_{M / G}=V_{M / R} \cos \theta+V_{R} \cos 30^{\circ} \\ \end{aligned}

\begin{aligned} V_{M / R} \sin \theta &=V_{R} \sin \left(30^{\circ}\right) \\ V_{M / R} &=V_{R}(\operatorname{Given}) \\ \sin \theta &=\sin 30^{\circ} \\ \theta &=30^{\circ} \end{aligned}

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vishal kumar

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