Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A system undergoes a process in which it absorbs of heat and does <img alt="150 \mathrm

A system undergoes a process in which it absorbs 200 \mathrm{~J} of heat and does 150 \mathrm{J} of work on its surroundings. Calculate the change in internal energy for this process.

Option: 1

50 J


Option: 2

200 J


Option: 3

350 J


Option: 4

-50 J


Answers (1)

best_answer

According to the first law of thermodynamics, \mathrm{\Delta U=Q+W}
where \mathrm{\Delta U} is the change in internal energy, Q is the heat transfer, and W is the work done on the system.

Substituting the values:

\mathrm{ Q=200 \mathrm{~J}, W=-150 \mathrm{~J} \text {. } }

Therefore, \mathrm{\Delta U=Q+W=200 \mathrm{~J}-150 \mathrm{~J}=50 \mathrm{~J}.}

Posted by

Rishabh

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 Session 2 Admit Card: NTA releases hall tickets for April 2, 4 exam at jeemain.nta.nic.in
anam-khan

JEE Mains 2026 Admit Card (Out) LIVE: NTA releases session 2 hall ticket; exam dates, pattern, marking scheme
anam-khan

Centre allows JEE Main 2026 rescheduling for Easter candidates, says Suresh Gopi

Latest Question