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  • A tangent galvanometer has a coil of 25 turns and radius of 15 cm. The horizontal component of earth's magnetic field is 3 * 10-5 T. The current required to produce a deflection

A tangent galvanometer has a coil of 25 turns and radius of 15 cm. The horizontal component of earth's magnetic field is 3 * 10-5 T. The current required to produce a deflection of 45o in it, is:

Option: 1

0.29 A


Option: 2

1.2 A


Option: 3

3.6 * 10-5 A


Option: 4

0.14 A


Answers (1)

best_answer

As we learn

Tangent Galvanometer -

B=B_{H}tan\Theta B=\frac{\mu _{o}ni}{2r}=B_{\mu tan\Theta } =k\:tan\Theta

- wherein

K=\frac{2rB_H}{\mu_0N}

r=radius of coil

\Theta =Angle made by needle

 

  i=\frac{2rBH}{\mu_oN}\tan\theta 

\Rightarrow i=\frac{2\times 15\times 10^{-2}\times 3 \times 10^{-5}}{4\pi \times 10^{-7}\times 25}\times\tan45^0 

\Rightarrow i = 0.29 A

Posted by

Ritika Jonwal

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