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  • A thermally insulated vessels contain  at water at <img alt="0^{\circ} \mathrm

A thermally insulated vessels contain 100 \mathrm{~g} at water at 0^{\circ} \mathrm{C}
Then The air from the vessels is pumped out adiabatically.

A fraction of water turns into ice and Rest evaporates at 0^{\circ} \mathrm{C}  itself. The Mass evaporated water will of close to
[Latent heat of vaporization of water = 2-10 \times 10^6 \mathrm{~J} / \mathrm{kg}
And latent heat of fusion of water = 3.36 \times 10^5 \mathrm{~J} / \mathrm{kg} ?]

Option: 1

20 \mathrm{~g}


Option: 2

\quad 9.4 \mathrm{~g}


Option: 3

150 \mathrm{~g}


Option: 4

200 \mathrm{~g}


Answers (1)

best_answer

suppose amount of water evaporated is M gram
Then \mathrm{(100-M)} grans of water is converted te ice.
So, heat consumed.

\text{ So Heat Compound in evaporation} \Rightarrow \text{ Heat Relaxed in Elusion}

\begin{aligned} &\mathrm{ M \times L V=(100-M) \times L S }\\ &\mathrm{ M \times 2.1 \times 10^6=(100-M) \times 3.36 \times 10^5 }\\ &\mathrm{ M \times 2.1 \times 10^{6}=100-M} \\ & 2.1 \times 10^6 \mathrm{M}=336 \times 10^5-3.36 \times 10^5\mathrm{M }\\ &M=9.4 \mathrm{~g} \end{aligned}

 

Posted by

Devendra Khairwa

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