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  • A thermally insulating cyelindical was a thermal insulting Frictionless movable portion in Middle, as show ns in given figure on each side of the partition, there is one Male of an i

A thermally insulating cyelindical was a thermal insulting Frictionless movable portion in Middle, as show ns in given figure

on each side of the partition, there is one Male of an ideal crab. with specific heat at constant volume \mathrm{C_V=4 R}, Here \mathrm{R} io Gas constant

Initially each side than a volume vo and Temperature To

The left side has an electric relater which is tweed at very low power to transfer Heat \mathrm{Q} to the gas on the lett side.

So a Result, the partition moves slowly toward the Right, Reducing the Right side volume to \mathrm{\frac{v_0}{y}}

Consequently the gas Temperature on the left and Right side

become \mathrm{T_L}  and \mathrm{T_R} Respectively.

Ignore the change in Temperature of cyclic, treater partition

The value of \frac{T_R}{T_O} is
 

Option: 1

(2)^{\frac{1}{2}}


Option: 2

(2)^{\frac{1}{4}}


Option: 3

(3)^{\frac{1}{4}}


Option: 4

(3)^{\frac{1}{2}}


Answers (1)

best_answer

\begin{aligned} &\mathrm{ P_r^r=c }\\ &\mathrm{ T v^{r-1}=c }\\ &\mathrm{ T_{0 v_0}^{r-1}=T R\left(\frac{v_0}{y}\right)^{r-1} }\\ &\mathrm{ c r=\frac{R}{r-1} }\\ &\mathrm{ 4 R=\frac{R}{r-1} }\\ &\mathrm{ r-1=\frac{1}{4} }\\ &\mathrm{ r=\frac{1}{4}+1=\frac{5}{4}}\\ &\mathrm{So~ \frac{5 R}{50}=2^{r-1}=2^{\frac{5-1}{4}}=(2)^{\frac{1}{4}}}\\ \end{aligned}

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Kuldeep Maurya

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