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A thin rod of length f/3 lies along the axis of a concave mirror of focal length f. One end of its magnified image touches an end of the rod. what is the length of image ?

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@Vishal

$v=-\frac{2f}{3}$

So rod length is 2f/3

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sudhir kumar

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@Vishal

Rod image length will be 2f/3 for that condition,

Solution I will send in the morning with diagram.

Posted by

sudhir kumar

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