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 A thin rod of length f/3 lies along the axis of a concave mirror of focal length f.  One end of its magnified image touches an end of the rod. what is the length of  image ?  

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@Vishal 

 v=-\frac{2f}{3}

So rod length is 2f/3

 

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sudhir.kumar

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@Vishal 

Rod image length will be 2f/3 for that condition,

Solution I will send in the morning with diagram.

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sudhir.kumar

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