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  • A transformer is having 2100 turns in primary and 4200 turns in secondary. An ac source of 120 V, 10 A is connected to its primary. The secondary voltage and current are:<div class='qna-option'

A transformer is having 2100 turns in primary and 4200 turns in secondary. An ac source of 120 V, 10 A is connected to its primary. The secondary voltage and current are:

Option: 1

 240 V, 5A 


Option: 2

120 V, 10 A 


Option: 3

240 V, 10 A


Option: 4

120 V, 20 A


Answers (1)

best_answer

\mathrm{\begin{aligned} & \text { As } \frac{\mathrm{V}_{\mathrm{s}}}{\mathrm{V}_{\mathrm{p}}}=\frac{\mathrm{N}_{\mathrm{s}}}{\mathrm{N}_{\mathrm{p}}} \\ & \therefore \quad \mathrm{V}_{\mathrm{s}}=\frac{\mathrm{N}_{\mathrm{s}}}{\mathrm{N}_{\mathrm{p}}} \mathrm{V}_{\mathrm{p}}=\frac{4200}{2100} \times 120=240 \mathrm{~V} \\ & \text { As } \frac{\mathrm{I}_{\mathrm{s}}}{\mathrm{I}_{\mathrm{p}}}=\frac{\mathrm{N}_{\mathrm{p}}}{\mathrm{N}_{\mathrm{s}}} \\ & \therefore \quad \mathrm{I}_{\mathrm{s}}=\frac{\mathrm{N}_{\mathrm{p}}}{\mathrm{N}_{\mathrm{s}}} \mathrm{I}_{\mathrm{p}}=\frac{2100}{4200} \times 10=5 \mathrm{~A} \end{aligned} }

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