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A transistor having\mathrm{\beta\;= 0.99}, is used in a common-base amplifier. If the load resistance is\mathrm{4.5 K\Omega }and the dynamic resistance of the emitter junction is  \mathrm{50 K\Omega }, the voltage gain of the amplifier will be:

Option: 1

79.1


Option: 2

89.1


Option: 3

99.1


Option: 4

None of these


Answers (1)

best_answer

\mathrm{\frac{\alpha R_L}{R_e}=\frac{0.99 \times 4500}{50}=89.1}

Posted by

Sanket Gandhi

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