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A transverse wave traveling on a stretched string is represented by the equation

y=\frac{2}{(2 x-6-2 t)^2+20} then

 

Option: 1

Velocity of the wave is 3.1m/s


Option: 2

Amplitude of the wave is 0.1m


Option: 3

Frequency of the wave is 20 Hz


Option: 4

Wavelength os the wave is 1m


Answers (1)

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velocity of the wave is, \begin{aligned} & v=\frac{\text { coefficient of } t}{\text { coefficient of } x} \\ & v=\frac{6.2}{2}=3.1 \mathrm{~m} / \mathrm{s} . \end{aligned}

Now, the amplitude of the wave, \begin{aligned} & A=\frac{2}{20} \\ & A=0.1 \mathrm{~m} \end{aligned}

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seema garhwal

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