Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • A triangle is formed by the lines whose combined equation is given by  <img alt="\mathrm{(x + y - 4) (xy - 2x - y + 2) = 0.}" src="https://entrancecorner.o

A triangle is formed by the lines whose combined equation is given by 

\mathrm{(x + y - 4) (xy - 2x - y + 2) = 0.}  The circumcentre of the circumcircle is  

Option: 1

(3/2, 5/2)

 


Option: 2

(-3/2, 5/2)

 


Option: 3

(3, 5)


Option: 4

(-3/2,-5/2)


Answers (1)

The sides are\mathrm{x + y - 4 = 0, x - 1 = 0, y - 2 = 0.} So, the triangle is right angled at (1, 2). 

The hypotenuse is\mathrm{x + y - 4 = 0} whose ends are (1, 3) and (2, 2). 

The circumcentre =\left(\frac{1+2}{2}, \frac{3+2}{2}\right) and

circumradius =\frac{1}{2} \sqrt{(1-2)^2+(3-2)^2}=\frac{1}{\sqrt{2}}

 

Posted by

Kshitij

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Latest Question