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A trisubstituted compound ' \mathrm{A}$ ', $\mathrm{C}_{10} \mathrm{H}_{12} \mathrm{O}_2 gives neutral \mathrm{FeCl}_3 test positive. Treatment of compound \mathrm{'A'} with \mathrm{NaOH}$ and $\mathrm{CH}_3 \mathrm{Br} gives \mathrm{C}_{11} \mathrm{H}_{14} \mathrm{O}_2, with hydroiodic acid gives methyl iodide and with hot conc. \mathrm{NaOH} gives a compound \mathrm{B}, \mathrm{C}_{10} \mathrm{H}_{12} \mathrm{O}_2. Compound \mathrm{'A'} also decolorises alkaline \mathrm{KMnO}_4. The number of \mathrm{\pi\: bond/s} present in the compound \mathrm{ ' \mathrm{A} '} is

Option: 1

4


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

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himanshu.meshram

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