Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

A uniform chain of length 2 m is kept on a table such that a length of 60 cm hangs freely from the edge of the table. The total mass of the chain is 4 kg . What is the work done in pulling the entire chain on the table ?

Answers (1)

best_answer

Consider a small part dx at a depth x from table. 

Work done in lifting this small portion is dw = dm gx

Total work done =\int dw=\int_{0}^{h}(\frac{m}{l}dx)gx

     

=\frac{mg}{l}\int_{0}^{h}x dx=\frac{4\times 10}{2}\times \frac{(0.6)^{2}}{2}=3.6J

 

Posted by

avinash.dongre

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2026 Registration LIVE: NTA session 1 exam from January 21; applications soon at jeemain.nta.nic.in
anam-khan

JEE Main 2026 exam dates out; session 1 on January 21-30; NTA to increase exam centres for wider reach
anam-khan

JEE Main 2026 Registration LIVE: NTA session 1 application form soon; exam date, syllabus updates

Latest Question