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  • A uniform cylindrical rod of length , cross -sectional area <img alt="A" src="https://entrancecorner.oncodecogs.com/gif.l

A uniform cylindrical rod of length L, cross -sectional area A and young's modulus Y is acted upon by the forces as shown in figure.

The rod is hinged at point P, \frac{L}{3} from the right end. The extension of the rod is -
 

Option: 1

\frac{4 F L}{3 A Y}


Option: 2

\frac{3 F L}{8 A Y}


Option: 3

\frac{2 F L}{5 A Y}


Option: 4

\frac{3 F L}{5 A Y}


Answers (1)

best_answer

Rod will extend on both sides of the hings, so-
\begin{aligned} & \Delta l=\frac{2 F\left(\frac{L}{3}\right)}{A Y}+\frac{F\left(\frac{2 L}{3}\right)}{A Y} \\ & \Delta l=\frac{4 F L}{3 A Y} \end{aligned}

Posted by

Rakesh

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