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A uniform electric field \underset{E}{\rightarrow} exists between the plates of a charged condenser. A charged particles enters the space between the plates and perpendicular to \underset{E}{\rightarrow}. The path of the particle between the plates is a :

Option: 1

Straight line 


Option: 2

Hyperbola 


Option: 3

Parabola


Option: 4

Circle


Answers (1)

best_answer

it will be parabolic. because the particle will be attracted towards the charged plate of its opposite sign.

there will be two motions asscoiated with a perpendicular motion to E and one along E.

for which the equation is as follows

y=1/2 qEx2/mv2

 where q is charge.... E is electric feild....m is mass and v is the initial velocity...

y=kx2 where k=1/2qE/mv2.

Posted by

Gautam harsolia

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