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 A uniform solid cylindrical roller of mass 'm' is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is 'a' and it is rolling without slipping then the value of 'F' is :

Option: 1

ma


Option: 2

 2 ma


Option: 3

\frac{3}{2}ma


Option: 4

\frac{5}{3}ma


Answers (1)

best_answer

As learnt in concept

Let f be frictional force

ma = F-f

\frac{mR^{2}}{2}\cdot \alpha = fR

\frac{mR^{2}}{2}.\frac{a}{R}=fR

\frac{ma}{2}=f \Rightarrow ma = F - \frac{ma}{2}

F=\frac{3ma}{2}

 

Posted by

sudhir.kumar

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