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  • A uniform steel bar of cross-sectional area A and length L is suspended so that it hangs vertically. The stress at the middle point of the bar is Option: 1<

A uniform steel bar of cross-sectional area A and length L is suspended so that it hangs vertically. The stress at the middle point of the bar is 

Option: 1

\frac{L}{2 A} \rho g


Option: 2

\frac{L \rho g}{2}


Option: 3

\frac{LA}{\rho g}


Option: 4

\mathrm{L \rho g}


Answers (1)

At middle, T = weight of half the length of steel bar

T=\left(\frac{L}{2}\right) A \rho g

\therefore  Stress = \frac{T}{A}=\frac{L \rho g}{2}

Posted by

Ramraj Saini

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