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  • A uniform string of length 60 m is suspended from a rigid support. A short wave Pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support

A uniform string of length 60 m is suspended from a rigid support. A short wave Pulse is introduced at its lowest end. It starts moving up the string. The time taken to reach the support is (take \small g=10 \mathrm{~m} / \mathrm{s}^2 )

Option: 1

2\sqrt{6}\ sec


Option: 2

3\ sec


Option: 3

3 \sqrt{2} \sec


Option: 4

2\sqrt{5} \sec


Answers (1)

best_answer

\text { Velocity at any } x=\sqrt{\frac{\mu x g}{\mu}}=\sqrt{x g}

\begin{aligned} v & =\sqrt{x \cdot g} \\ \frac{d x}{d t} & =\sqrt{x \cdot g} \\ \int_0^L \frac{d x}{\sqrt{x}} & =\int_0^T \frac{T}{g} d t \\ \\ {[2 \sqrt{x}]_0^L } & =\sqrt{g}[J] T_0 \\ \\ 2 \sqrt{L}-0 & =\sqrt{g} T \\ T & =2 \sqrt{\frac{L}{g}} \end{aligned}

\begin{aligned} T & =2 \sqrt{\frac{60}{10}} \\ T & =2 \sqrt{6} \mathrm{sec} \end{aligned}

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avinash.dongre

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