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A vertex of an equilateral triangle is \mathrm{(2,3)} and the opposite side is \mathrm{x+y=2}. Find the equation of the other sides.

 

Option: 1

\mathrm{y-3=(\sqrt{2} \pm 1)(x-2)}


Option: 2

\mathrm{y-3= \pm \sqrt{2}(x-2)}


Option: 3

\mathrm{y-3=(2 \pm \sqrt{3})(x-2)}


Option: 4

\mathrm{y-3= \pm \sqrt{3}(x-2)}


Answers (1)

best_answer

Slope of line \mathrm{B C=-1}
\mathrm{\therefore} Slope of line \mathrm{A D=1}
\mathrm{ \begin{aligned} & \tan 30=\frac{\boldsymbol{m}-1}{1+\boldsymbol{m}}= \pm \frac{1}{\sqrt{3}} \\ & m=(2+\sqrt{3}),(2-\sqrt{3}), \end{aligned} }
equation of the other lines
\mathrm{ \begin{aligned} & y-3=(2+\sqrt{3})(x-2) \\ & y-3=(2-\sqrt{3})(x-2) \end{aligned} }

Posted by

Devendra Khairwa

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