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A vibrating tuning fork of frequency n is placed near the open end of a long cylindrical tube. The tube has a side opening and is alto fitted with a movable reflecting Poston. As the piston is moved through 4.65 \mathrm{~cm}, the intensity of sound changes from a maximum to minimum. If the speed of sound is 400 \mathrm{~m} / \mathrm{s} then n.

Option: 1

21.5054


Option: 2

23.4506


Option: 3

22.5056


Option: 4

26.4534


Answers (1)

best_answer

Path difference =4.65 \times 2

Path difference=\frac{\lambda}{2}

\therefore \quad 9 \cdot 3=\frac{\lambda}{2} \\

 \lambda=18 \cdot 6 \\\lambda=18.6

v =n \lambda \\

n=\frac{u}{\lambda} \\

n =\frac{400}{18.6} \\

n=\frac{4000}{186} \\

 n=21.5054

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HARSH KANKARIA

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