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A wire is bent to form a square loop of side a it carries a current I and is kept with its plane perpendicular to a uniform magnetic field. Shape of the loop is changed from square to a circle without changing the length of the wire and current then:

Option: 1

The magnetic moment of square loop with respect to circular loop is \mathrm{{ia }^2\left(1-\frac{4}{\pi}\right)}
 


Option: 2

The magnetic moment of square loop with respect to circular loop is \mathrm{{ia }^2\left(1-\frac{2}{\pi}\right)}
 


Option: 3

The amount of work done in doing so is \frac{\mathrm{iBa}^2}{\pi}(\pi-4)


Option: 4

The amount of work done in doing so is \frac{\mathrm{ia}^2}{4}(\pi-4)


Answers (1)

best_answer

\mathrm{ \text { Ratio of area }=\frac{a^2}{\pi\left(\frac{4 a}{2 \pi}\right)^2} }
\mathrm{\left(\frac{\text { square }}{\text { circle }}\right) \quad=\frac{\pi}{4} }
 

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Anam Khan

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