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 A wire of length L and 3 identical cells of negligible internal resistance are connected in series. Due to the current, the temperature of the wire is raised by \Delta T in a time t. A number N of similar cells is now connected in series with a wire of the same material and cross section but of length 2L. The temperature of the wire is raised by the same amount \Delta T in the same time t. The value of N is

Option: 1

4


Option: 2

6


Option: 3

8


Option: 4

9


Answers (1)

best_answer

\frac{\left((3 \varepsilon)^2 /(\rho \ell / \mathrm{A})\right)}{\left((\mathrm{N} \varepsilon)^2 /(\rho 2 \ell / \mathrm{A})\right)}=\frac{(\ell \mathrm{Ad}) \mathrm{s} \Delta \mathrm{T}}{(2 \ell \mathrm{Ad}) \mathrm{s} \Delta \mathrm{T}}

Here \rho is resistivity, d is density and s is specific heat
capacity of material of the wire.

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chirag

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