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A zener diode, having breakdown voltage equal to 15 \mathrm{~V}, is used in a voltage regulator circuit shown in figure. The current through the diode is

Option: 1

20 \mathrm{~mA}


Option: 2

5 \mathrm{~mA}


Option: 3

10 \mathrm{~mA}


Option: 4

15 \mathrm{~mA}


Answers (1)

best_answer

Voltage across zener diode is constant

\mathrm{\begin{aligned} &i_{1 k \Omega}=\frac{15 \text { volt }}{1 k \Omega}=15 \mathrm{~mA}\\ &\begin{aligned} & i_{250 \Omega}=\frac{(20-15) V}{250 \Omega}=\frac{5 \mathrm{~V}}{250 \Omega}=\frac{20}{1000} A=20 \mathrm{~mA} \\ & \therefore i_{\text {zener diode }}=(20-15)=5 \mathrm{~mA} \end{aligned} \end{aligned} }

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