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  • AB and CD are two uniform resistance wires of lengths 100 cm and 80 cm respectively. The connections are shown in the figure. The cell of emf 5 V is ideal while the other cell of emf E has internal

AB and CD are two uniform resistance wires of lengths 100 cm and 80 cm respectively. The connections are shown in the figure. The cell of emf 5 V is ideal while the other cell of emf E has internal resistance 2\Omega A length of 20 cm of wire CD is balanced by 40 cm of wire AB. Find the value of x if E = 2x, where E is emf of cell in volt. The reading of the ideal ammeter is 2 A. The other connecting wires have negligible resistance

Option: 1

2


Option: 2

3


Option: 3

5


Option: 4

6


Answers (1)

best_answer

The potential difference across wire AB = 5 V

\therefore P.D. across 40 cm of this wire =\frac{5}{100}\times 40=2 volt

Potential Difference across 20 cm of wire CD = 2 volts.

P.D. across wire CD=\frac{2}{20}\times 80=8\; volt

P.D. across  2 \Omega resistor =  2 \times 2=4 \text { volt }

Emf of the cell   = 12 volts.

                                  x = 6

Posted by

seema garhwal

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