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  • Among the following species <img alt="\mathrm{N}_{2}, \mathrm{~N{_{2}}^{+}}, \mathrm{N{_{2}}^{-}}, \mathrm{N{_{2}}^{2-}}, \mathrm{O}_{2}, \mathrm{O{_{2}}^{+}}, \mathrm{O{_{2}}^{-}},\mathr

Among the following species

\mathrm{N}_{2}, \mathrm{~N{_{2}}^{+}}, \mathrm{N{_{2}}^{-}}, \mathrm{N{_{2}}^{2-}}, \mathrm{O}_{2}, \mathrm{O{_{2}}^{+}}, \mathrm{O{_{2}}^{-}},\mathrm{O{_{2}}^{2-}}

the number of species showing diamagnesim is __________.

Option: 1

2


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

According to MOT , if all electrons are paired , then that species will show diamagnesim property.

\begin{aligned} & \mathrm{M_2: \sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \pi 2 P_x^2=\pi 2 P_y^2, \sigma 2 P_z^2} \end{aligned}

\begin{aligned} & \mathrm{N_2^{+}: \sigma 1 s^2, \sigma ^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \pi 2 P_2^2=\pi 2 P_4^2, \sigma 2 P_z^1} \end{aligned}

\begin{aligned} & \mathrm{N_2^{-}: \sigma 2 s^2, \sigma ^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \pi 2 p_x^2=\pi 2 p_y^2, \sigma 2 p_2^2, \pi^* 2} \end{aligned}

\begin{aligned} & \mathrm{N_2^{2-}=\sigma 2 s^2, \sigma ^{*} 1s^2, \sigma 2 s^2, \sigma ^* 2 s^2, \pi 2 p_x^2=\pi 2 p_y^2, \sigma 2 p_z^2 \text {, }} \end{aligned}

                  \begin{aligned} & \mathrm{\pi^* 2 P_x^{1}=\pi^* 2 P_y^{1}} \end{aligned}

\mathrm{\mathrm{O}_2: \sigma 1 s^2, \sigma ^* 1 s^2, \sigma 2 s^2, \sigma ^* 2 s^2, \sigma 2 P_z^2 ; \pi 2 P_x^2=\pi 2 P_y^2, \pi^* 2 P_x^1=\pi ^{*}2 P_y^1}

\mathrm{O_2^{-}: \sigma 1 s^2, \sigma ^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 P_z^2, \pi 2 P_x^2=\pi 2 P_y^2, \pi^* 2 P_x^2=\pi^* 2 P_y^2,}

\mathrm{O_2^{+}: \sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma^{2}P_2^2, \pi 2 P_x^2=\pi 2 P_y^2, \pi^* 2 P_x^2=\pi^* 2 P_y^0}

\mathrm{O_2^{2-}: \sigma 1 s^2, \sigma ^* 1 s^2, \sigma 2 s^2, 6^* 2 s^2, \sigma 2 p_z^2, \pi 2 p_x^2=\pi 2 P_y^2, \pi^* 2 P_x^2=\pi^{*} 2 P_y^2}
\mathrm{N}_2 \text{ and } \mathrm{O}_2^{2-} all electrons are paired. Both of them will show diamagnetism.

Posted by

seema garhwal

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