Get Answers to all your Questions

header-bg qa

Among the statements :

\mathrm{(S1): (p \Rightarrow q) \vee ((\sim p) \wedge q)} is a tautology

\mathrm{(S2): (q\Rightarrow p) \Rightarrow ((\sim p) \wedge q)} is a contradiction

Option: 1

only (S2) is True


Option: 2

only (S1) is True
 


Option: 3

neigher (S1) and (S2) is True


Option: 4

both (S1) and (S2) are True


Answers (1)

P Q \mathrm{\sim p} \mathrm{\sim p\wedge q} \mathrm{\sim p\Rightarrow q} \mathrm{(\sim p\Rightarrow q)v(\sim p\wedge q)}
T T F F T T
T F F F F F
F T T T T

T

F F T F T T

S2

P Q q\Rightarrow p \sim p (\sim p)\wedge q \mathrm{(q\Rightarrow p)\Rightarrow (\sim p\wedge q)}
T T T F F F
T F T F F F
F T F T T

T

F F T T F F

Correct Answer is option 3   

 

Posted by

Kshitij

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE