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An ac voltage is applied to a resistance R and an inductor L in series. If R and the inductive reactance are both equal to 3\Omega , the phase difference between the applied voltage and the current in the circuit is:

Option: 1

\frac{\pi}{6}


Option: 2

\frac{\pi}{4}


Option: 3

\frac{\pi}{2}


Option: 4

zero


Answers (1)

best_answer

Here, \mathrm{\mathrm{R}=3 \Omega, \mathrm{X}_{\mathrm{L}}=3 \Omega }

If \mathrm{\phi } is the phase difference between the applied voltage and the current in the circuit,

then 
\mathrm{\tan \phi=\frac{\mathrm{X}_{\mathrm{L}}}{\mathrm{R}}=\frac{3}{3} \quad or \phi=\frac{\pi}{4} }

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Pankaj

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