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An air bubble of diameter 6 mm rises steadily through a solution of density 1750 kg/m^{3}at the rate of 0.35 cm/s.
Calculate the co-efficient of viscosity of the solution (neglect density of air) is __________ Pas (given, g = 10 ms^{-2}).

Option: 1

10


Option: 2

____


Option: 3

____


Option: 4

___


Answers (1)


For uniform velocity net force= 0
\begin{aligned} & B=6 \pi \eta r v \\ & \rho \frac{4}{3} \pi r^3 g=6 \pi \eta r v \\ & \eta=\frac{2 \rho r^2 g}{9 \mathrm{v}} \\ & \eta=\frac{2 \times 1750 \times\left(3 \times 10^{-3}\right)^2 \times 10}{9 \times 0.35 \times 10^{-2}} \\ & \eta=10 \mathrm{~Pa}-\mathrm{s} \end{aligned}

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Kshitij

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