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An alternating e.m.f. \mathrm{100 \cos 100 t} volt is connected in series to a resistance of 10 ohm and inductance 100 mH. What is the phase difference between the current in the circuit and the e.m.f.?

Option: 1

\frac{\pi}{4}


Option: 2

zero


Option: 3

{\pi}


Option: 4

\frac{\pi}{2}


Answers (1)

\mathrm{\begin{aligned} & \cos \phi=\frac{R}{Z}=\frac{R}{\sqrt{X_L^2+R^2}}, \quad R=10 \Omega, X_L=\omega L=10 \Omega \\ & \therefore \quad \cos \phi=\frac{1}{\sqrt{2}} \quad \text { or } \quad \phi=\frac{\pi}{4} \\ & \end{aligned}}

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Sumit Saini

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